**What speed have to travel Jon at the wheel of fortune?**

*Jon together a ferris wheel with a radius of 25 feet. The board of the wheel at a height* 3 feet. above the ground (lowest point). Turn 3rpm speed. Write the equation for the height at time t. Jons

rotational speed Jon is 22 (pi / 10) m / s = 6.9115 … ft / s, and the height "h" above the ground in time 't' is h = 3 + 22 (1 – cos wt) m = 3 + 22 (1 – pi [cos (t / 10)]) [ft Jon describe the motion of the term "rotational speed", because its speed has a constant magnitude, but dorection is always changing, of course.] A turnover rate of 3 rpm (revolutions per minute 3) gives ANGULAR 'W Speed "one of w = 3 x (2 pi) radians per minute, or 6 pi / 60 rad / s = pi / 10 rad / s. Jon is at r = 22 m from the center of the wheel, so that its speed is wr = 22 (pi / 10) m / s = 6.9115 … ft / s. height "h It's above the ground at the time 't' is h = 3 + 22 (1 – cos wt) = ft 3 + 22 (1 – pi [cos (t / 10)]) feet long live and prosper.

**How to travel on-road with a Volvo Wheeled Excavator (Part 5 of 16)**

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